12. The average power output of the source is 910emit7.2 nJ3.6 nJ/s3.6 10 J/s2.25 10 eV/s2sEPt−∆====×=×∆Since the energy of each photon emitted is ph1240 eV nm2.07 eV600nmhcEλ⋅=, the rate at which photons are emitted by the source is 1010emitemitph2.25 10 eV/s1.09 10 photons/s.2.07 eVPRE×=×Given that the source is isotropic, and the detector (located 12.0 m away) has an
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.