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abs
abs
emit
2
(0.80)
.
4
A
RR
r
π
=
Given that
62
abs
2.00 10 m
A
−
=×
and
3.00 m,
r
=
with
abs
4.000 photons/s,
R
=
we find the
rate at which photon is emitted to be
()
22
8
emit
abs
abs
44
(
3
.
0
0
m
)
4.000 photons/s
2.83 10 photons/s
(0.80)
(0.80)(2.00 10 m )
r
A
ππ
−
==
=
×
×
.
Since the energy of each emitted photon is
ph
1240 eV nm
2.48 eV
500nm
hc
E
λ
⋅
=
,
the power output of source is
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 Spring '08
 Any
 Physics, Photon, Light

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