Ch38-p018 - 18 We use Eq 38-5 to find the maximum kinetic energy of the ejected electrons c hc h Kmax = hf = 4.14 1015 eV s 3.0 1015 Hz 2.3 eV =

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18. We use Eq. 38-5 to find the maximum kinetic energy of the ejected electrons: Kh f max
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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