ch38-p021 - 21(a The kinetic energy Km of the fastest...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
21. (a) The kinetic energy K m of the fastest electron emitted is given by K m = hf Φ = ( hc / λ ) – Φ , where Φ is the work function of aluminum, f is the frequency of the incident radiation, and λ is its wavelength. The relationship f = c / λ was used to obtain the second form. Thus, K m = 1240 200 420 eV nm nm eV = 2.00 eV ., where we have used hc = 1240 eV·nm. (b) The slowest electron just breaks free of the surface and so has zero kinetic energy.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online