()121511171.85eV 0.820eV4.12 10eV s.3.00 10 nm/s300nm400nmeV Vhc−−−−−===×⋅⎡⎤λ−λ×−⎣⎦(b) The work function is Φ=−−=−−=3082018530040022722(.(..VVλλeV)(400 nm)eV)(300 nm)nmeV. (c) Let Φ= hc/λmaxto obtain λmax.⋅=hcΦ1240545eV nmeVnm. 26. (a) For the first and second case (labeled 1 and 2) we have
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.