ch38-p031 - 31. (a) The fractional change is E (hc / ) 1 1...

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11 9 10 1 1 8.1 10 8.1 10 %. (3.0 10 pm/2.43pm)(1 cos90 ) 1 E E −− =− × × ×− ° + (b) Now λ = 500 nm = 5.00 × 10 5 pm and φ = 90°, so 64 51 1 4.9 10 4.9 10 %. (5.00 10 pm/2.43pm)(1 cos90 ) 1 E E × × ° + (c) With λ = 25 pm and = 90°, we find 2 1 1 8.9 10 8.9 %. (25pm/2.43pm)(1 cos90 ) 1 E E × −° + (d) In this case, λ = hc / E = 1240 nm·eV/1.0 MeV = 1.24 × 10 –3 nm = 1.24 pm, so 1 1 0.66 66 %. (1.24pm/2.43pm)(1 cos90 ) 1 E E + (e) From the calculation above, we see that the shorter the wavelength the greater the fractional energy change for the photon as a result of the Compton scattering. Since E / E is virtually zero for microwave and visible light, the Compton effect is significant only in
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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