ch38-p033 - 33. (a) Since the mass of an electron is m =...

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λ C h mc == ×⋅ ×× = 6 626 10 9109 10 2 426 10 2 43 34 31 12 . (. .. Js kg)(2.998 10 m / s) mp m . 8 (b) Since the mass of a proton is m = 1.673 × 10 –27 kg, its Compton wavelength is λ C = = 6 626 10 1673 10 1321 10 132 34 27 15 . kg)(2.998 10 m / s) mf m . 8 (c) We note that hc = 1240 eV·nm, which gives E = (1240 eV·nm)/ λ , where E is the energy and λ is the wavelength. Thus for the electron,
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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