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where
L
is the perpendicular distance between the slits and the screen. Therefore, the
angle between the center of the pattern and the second minimum is given by
2
3
tan
2
y
Ld
λ
θ
==
.
Since
d
±
, tan
≈
, and we obtain
16
86
9
33
(
1
.
8
9
1
0
m
)
7.07 10 rad
(4.0 10 )
22
(
4
.
0
0
1
0
m
)
d
−
−−
−
×
≈=
=
×
=
×
°
×
.
44. Using Eq. 378, we find the Lorentz factor to be
11
7.0888
1 ( / )
1 (0.9900)
vc
γ
=
.
With
p
mv
=
(Eq. 3741), the de Broglie wavelength of the protons is
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 Spring '08
 Any
 Physics

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