The wavelength is 691240eV nm1.24 10 nm 1.24 fm.1.00 10 eVhhcppc−⋅λ====×=×45. (a) The momentum of the photon is given by p = E/c, where Eis its energy. Its wavelength is ==⋅=hphcE12401001240eV nmeVnm..(b) The momentum of the electron is given by pmK=2, where Kis its kinetic energy and mis its mass. Its wavelength is =hphmK2. If Kis given in electron volts, then 3491/21/23119J s1.226 10 m eV1.226nm eV.2(9.109 10kg)(1.602 10J/eV)KKK−−6.626×10⋅×⋅⋅==××For 1.00 eVK=, we have 1/21.226nm eV
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.