The wavelength is
6
9
1240eV nm
1.24 10 nm 1.24 fm.
1.00 10 eV
hh
c
pp
c
−
⋅
λ=
=
=
=
×
=
×
45. (a) The momentum of the photon is given by
p = E
/
c
, where
E
is its energy. Its
wavelength is
=
=
⋅
=
h
p
hc
E
1240
100
1240
eV nm
eV
nm.
.
(b) The momentum of the electron is given by
pm
K
=
2
, where
K
is its kinetic energy
and
m
is its mass. Its wavelength is
=
h
p
h
mK
2
.
If
K
is given in electron volts, then
34
9
1/2
1/2
31
19
J s
1.226 10 m eV
1.226nm eV
.
2(9.109 10
kg)(1.602 10
J/eV)
KK
K
−−
6.626×10
⋅
×
⋅
⋅
=
=
××
For
1.00 eV
K
=
, we have
1/2
1.226nm eV
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Energy, Kinetic Energy, Mass, Momentum, Photon

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