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49. If
K
is given in electron volts, then
34
9
1/2
31
19
1/2
J s
1.226 10 m eV
2
2(9.109 10
kg)(1.602 10
J/eV)
1.226nm eV
,
hh
p
mK
K
K
K
−−
6.626×10
⋅
×
⋅
λ=
=
=
=
××
⋅
=
where
K
is the kinetic energy. Thus,
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Energy, Kinetic Energy

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