ch38-p064 - 64(a Using the value hc = 1240nm eV we have E=...

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64. (a) Using the value 1240nm eV hc =⋅ , we have E hc == × = λ 1240 10 0 10 124 3 nm eV nm keV . . (b) The kinetic energy gained by the electron is equal to the energy decrease of the photon: () ( ) 10.0pm 1co s 2.43pm 1 cos180 11 1 124keV 1 1 40.5keV. C hc hc E Eh c E φ λ λ− −° ∆λ ⎛⎞ ∆= = = = ⎜⎟ λ λ λ+∆λ λ λ+∆λ
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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