64. (a) Using the value 1240nm eVhc=⋅, we have Ehc==⋅×=−λ124010 0 101243nm eVnmkeV.. (b) The kinetic energy gained by the electron is equal to the energy decrease of the photon: ()()10.0pm1cos2.43pm 1 cos180111124keV1140.5keV.ChchcEEhcEφλλ−−°∆λ⎛⎞⎛⎞⎛⎞∆=∆=−==⎜⎟⎜⎟⎜⎟λλ λ+∆λλλ+∆λ
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.