ch38-p076 - 76. We substitute the classical relationship...

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λ= 6.626 10 ×⋅ ×× = = −− 34 31 19 9 2 9109 10 1226 10 1226 Js kg)(1.602 10 J / eV) meV nm eV 1/2 1/2 (. . . . K K K 76. We substitute the classical relationship between momentum p and velocity v, v = p / m into the classical definition of kinetic energy, Km v = 1 2 2 to obtain K = p 2 /2 m . Here
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