λ=6.626 10−×⋅××==⋅−−−34311992 9109 101226 101226Jskg)(1.602 10J / eV)meVnm eV1/21/2(....KKK76. We substitute the classical relationship between momentum pand velocity v, v = p/minto the classical definition of kinetic energy, Kmv=122to obtain K = p2/2m. Here
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