ch38-p081 - 81. We note that | eikx |2 = (eikx ) (eikx ) =...

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81. We note that ||() () . ee e e e ikx ikx ikx ikx ikx 2 1 == = ∗− Referring to Eq. 38-14, we see therefore that | |
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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