This preview shows page 1. Sign up to view the full content.
λ=
=
−
c
f
mL c
hn
n
fi
8
2
22
di
.
We evaluate this expression for
n
i
= 1 and
n
f
= 2, 3, 4, and 5, in turn. We use
h
= 6.626
×
10
– 34
J · s,
m
= 9.109
×
10
– 31
kg, and
L
= 250
×
10
– 12
m, and obtain the following results:
(a) 6.87
×
10
– 8
m for
n
f
= 2, (the longest wavelength).
(b) 2.58
×
10
– 8
m for
n
f
= 3, (the second longest wavelength).
(c) 1.37
×
10
– 8
m for
n
f
= 4, (the third longest wavelength).
10. The energy levels are given by
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Energy, Mass, Light

Click to edit the document details