2/422sin2sin0.091.24LyyydyLπππ⎛⎞⎛⎞=−=⎜⎟⎜⎟⎝⎠⎝⎠∫(c) For the region 3 /4LxL≤≤, we obtain 3/442sin2sin0.82yL⎛⎞=⎜⎟⎝⎠∫which we could also have gotten by subtracting the results of part (a) and (b) from 1; that is, 1 – 2(0.091) = 0.82. 14. We follow Sample Problem 39-3 in the presentation of this solution. The integration result quoted below is discussed in a little more detail in that Sample Problem. We note that the arguments of the sine functions used below are in radians.
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