Therefore, nlow= 1, but what precisely is nhigh? lowhigh2213.6eV13.6eV10.2eV1EEEn=+∆⇒−=−+which yields n= 2 (this is confirmed by the calculation found from Sample Problem 39-6). Thus, the transition is from the n= 2 to the n= 1 state. (a) The higher quantum number is
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.