ch39-p042 - 42. Using Eq. 39-6 and hc = 1240 eV nm, we find...

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Therefore, n low = 1, but what precisely is n high ? low high 22 13.6eV 13.6eV 10.2eV 1 EE E n =+ = + which yields n = 2 (this is confirmed by the calculation found from Sample Problem 39- 6). Thus, the transition is from the n = 2 to the n = 1 state. (a) The higher quantum number is
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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