This preview shows page 1. Sign up to view the full content.
Therefore,
n
low
= 1, but what precisely is
n
high
?
low
high
22
13.6eV
13.6eV
10.2eV
1
EE
E
n
=+
∆
⇒
−
=
−
+
which yields
n
= 2 (this is confirmed by the calculation found from Sample Problem 39
6). Thus, the transition is from the
n
= 2 to the
n
= 1 state.
(a) The higher quantum number is
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Photon

Click to edit the document details