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48. (a) Since
E
2
= – 0.85 eV and
E
1
= – 13.6 eV + 10.2 eV = – 3.4 eV, the photon energy
is
E
photon
=
E
2
–
E
1
= – 0.85 eV – (– 3.4 eV) = 2.6 eV.
(b) From
EE
nn
21
2
2
1
2
136
11
26
−=
−
−
F
H
G
I
K
J
=
(.
)
.
eV
eV
we obtain
112
6
3
16
1
4
1
2
2
2
1
22
2
≈
−=−
.
.
.
eV
eV
Thus,
n
2
= 4 and
n
1
= 2. So the transition is from the
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 Spring '08
 Any
 Physics, Energy, Photon

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