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52. Using Eq. 396 and
hc
= 1240 eV · nm, we find
photon
1240 eV nm
12.09 eV.
106.6 nm
hc
EE
λ
⋅
∆=
= =
=
Therefore,
n
low
= 1, but what precisely is
n
high
?
high
low
22
13.6eV
13.6eV
12.09eV
1
E
n
=+
∆
⇒
−
=
−
+
which yields
n
= 3. Thus, the transition is from the
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Photon

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