Ch 2 drill problem

Ch 2 drill problem - 121 mg x 1 g x 10 dL 1 L x 1.00 mL =...

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The triglyceride content of the blood of an individual is 121 mg/dL. What is the number of grams of triglycerides in 1.00 mL of this blood?
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Unformatted text preview: 121 mg x 1 g x 10 dL 1 L x 1.00 mL = 0.00121 g or 1.21 x 10-3 g dL 1000 mg 1 L 1000 mL...
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