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Unformatted text preview: 3 (g) at 25 o C. R = 0.0821 L atm mol1 K1 P = ? T = 25 o C + 273 = 298 K V = 500 mL = 0.500 L n = 0.452 g NH 3 x 1 mol = 0.0266 mol NH 3 17.0 g PV = nRT P = nRT V P = 0.0266 mol x 0.0821 L atm mol1 K1 x 298 K 0.500 L P = 1.30 atm Drill Problem: The partial pressure of N 2 on Denali is 288 torr on a day when the atmospheric pressure is 0.480 atm. What is the partial pressure of O 2 ? P N2 = 288 torr P total = 0.480 atm = 365 torr P O2 = ? P total = P 1 + P 2 + P 3 + …. . P O2 = P total – P N2 = 365 – 288 = 77 torr...
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This note was uploaded on 06/03/2011 for the course CHM 123 taught by Professor Woodward during the Fall '08 term at Ohio State.
 Fall '08
 WOODWARD
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