p111_lecture19

p111_lecture19 - acceleration of 0.800 m/s 2 . The radius...

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8.6 Rolling Motion Consider a car moving with a linear velocity, v . The tangential speed of a point on the outer edge of the tire is equal to the speed of the car over the ground. v = v T = r ω Also, the tangential acceleration of a point on the outer edge of the tire is equal to the acceleration of the car over the ground. a = a T = r α
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8.6 Rolling Motion Example 8 An Accelerating Car Starting from rest, the car accelerates for 20.0 s with a constant linear
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Unformatted text preview: acceleration of 0.800 m/s 2 . The radius of the tires is 0.330 m. What is the angle through which each wheel has rotated? 8.6 Rolling Motion 2 2 1 t t o ! " # + = 20.0 s 0 rad/s-2.42 rad/s 2 ? t o 2 2 s rad 42 . 2 m 0.330 s m 800 . = = = r a ( ) ( ) rad 484 s . 20 s rad 42 . 2 2 2 2 2 1 ! = ! = = -2.42 rad/s 2 since the wheels go clockwise...
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p111_lecture19 - acceleration of 0.800 m/s 2 . The radius...

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