news_041911

news_041911 - r E n =-ke 2 2 a n 2 =-13 . 6 ev n 2 a = ....

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Stuff for Tuesday, April 19, 2011 Sm1094 session tomorrow. Quiz #4 Friday. Midterm: Any 2 hours here from 6:30 to 10pm on Tuesday, May 3. 1 Quanton in a box: V ( x ) = 0 for 0 x L and infinite outside. ψ E n ( x ) = ± A sin n π x L if 0 x L 0 outside E n = h 2 n 2 8 mL 2 = p 2 n 2 m , p n = h λ n = h ( 2 L / n ) 2 Harmonic oscillator: V ( x ) = 1 2 k s x 2 = 1 2 m ω 2 x 2 ( ω = p k s / m ) E n = h ω 2 π ( n + 1 2 ) = ~ ω ( n + 1 2 ) , n = 0 , 1 , 2 ,... (cf. quanton in box: n = 1 , 2 , 3 ,... ) 3 Bohr model of hydrogen atom: circular orbit of radius
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Unformatted text preview: r E n =-ke 2 2 a n 2 =-13 . 6 ev n 2 a = . 053 nm (Bohr radius) , r n = n 2 a Spectral lines: E photon = E i-E f = hc emitted = = hc / E photon box 1 / ( n 2 i-n 2 f ) , HO 1 / ( n i-n f ) , Bohr n 2 i n 2 f / ( n 2 i-n 2 f )...
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This note was uploaded on 06/03/2011 for the course H 133 taught by Professor Furnstahl during the Spring '11 term at Ohio State.

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