news_053111

news_053111 - T ε ² T Entropy of a monatomic gas Ω U V N...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Stuff for Tuesday, May 31, 2011 Schedule for this week PS #17 due today; PS #18 due Friday 1094 Session 9 on Wednesday and quiz #9 on Friday T6, T7, T8 stuff: Entropy S = k b ln Ω , so Ω = e S / k b ; S /∂ U 1 / T defines temperature Maxwell-Boltzmann: Probability of molecule speed v is e - E / k B T = e - mv 2 / 2 k B T Pr(speed v ± dv / 2) = 4 π v v P « 2 e - ( v / v P ) 2 dv v P where v P 2 k B T m « 1 / 2 Average energy of a quantum system E avg = X n E n Pr ( E n ) = X n E n e - En / k B T / X n e - En / k B T Characteristic temperature T ε ε/ k B ; dof’s switched off if
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: T ε ² T Entropy of a monatomic gas Ω( U , V , N ) ≈ 1 N ! „ 8 mV 2 / 3 bU 3 Nh 2 « 3 N / 2 S ( U , V , N ) = 3 2 Nk B ln „ 8 mV 2 / 3 bU 3 Nh 2 «-k B ln ( N !) Entropy change: dS = dQ / T with constant N , only work from quasistatic Δ V constant T : Δ S = Q T phase change: Q = ± mL specific heat: Δ S = mc ln T f T i...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online