Exam review partial key

Exam review partial key - Partial Key Exam One Review...

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Partial Key Exam One Review Example One c 10 21 9 7 3 0 5 10 15 20 25 0<15 15<30 30<45 45<60 60<75 # of email Frequecny Example Two The following data reflects travel expenses (in dollars)for 23 salespeople last month at CalSpar Inc. 897 1482 1698 1961 1036 1499 1701 2031 1169 1541 1727 1335 1567 1824 1354 1578 1829 1448 1584 1919 1471 1696 1926 a. List the five number summary for the data. Min = 897 Q1= 1448 Q2 = 1578 Q3= 1824 Max = 2031 b. Construcct a box plot for the data. Are there any outliers? Justify your response. Check for outliers: LL = Q1-1.5*IR = 1448-1.5(1824-1448)=1448-1.5*376=884 (so, no low outliers) UL = Q3+1.5*IR = 1824+1.5*IR = 1824+564=2388 (so, no high outliers) Class Freq Rel Freq Cum Freq Cum% Freq 0<15 10 0.2 10 20 15<30 21 0.42 31 62 30<45 9 0.18 49 98 45<60 7 0.14 47 94 60<75 3 0.06 50 100
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Example Three mean 62 median 62 mode 64 variance 70.33 std dev 8.39 Since mean = median, data is not skewed. For Chebyshev’s, at least 75% of data is within 2 std dev from the mean.
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Exam review partial key - Partial Key Exam One Review...

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