4_1b - Solutions 4.1-Page 273 Problem 25 Use the transforms...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Solutions 4.1-Page 273 Problem 25 Use the transforms in Fig. 4.1.2 to find the inverse Laplace transforms of the functions. 2 / 5 2 1 ) ( s s s F = From Fig. 4.1.2, s 1 corresponds to 1 ) ( = t f . The form of 2 / 5 2 s corresponds to with a t t f = ) ( 2 / 3 = a . π ) 4 / 3 ( ) 2 / 1 ( ) 2 / 1 )( 2 / 3 ( ) 1 2 / 1 ( ) 2 / 3 ( ) 2 / 3 ( ) 2 / 3 ( ) 1 2 / 3 ( = Γ = + Γ = Γ = + Γ because = Γ ) 2 / 1 ( according to pg.267. The form of the inverse Laplace function must be multiplied by 3 8 to get the correct function. 3 8 1 ) ( 2 / 3 t t f =
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Use the transforms in Fig. 4.1.2 to find the inverse Laplace transforms of the functions. 9 3 5 ) ( 2 + = s s s F The transform can be rewritten as 9 3 9 5 ) ( 2 2 + + = s s s s F 9 5 2 + s corresponds to an inverse of the form sin where kt 3 = k . With , the inverse is 3 = k 9 3 2 + s . This inverse must be multiplied by 5/3 in order to get 9 5 2 + s . 9
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 06/06/2011 for the course EGM 3311 taught by Professor Haftka during the Spring '11 term at University of Florida.

Page1 / 4

4_1b - Solutions 4.1-Page 273 Problem 25 Use the transforms...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online