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Unformatted text preview: the shear flow from static equivalence of the shear flow and shear forces. Answers: The shear flow in the circular segment is 209N/cm clockwise, and in the straight members 41 N/cm counter clockwise. The twist angle is 10-7 counterclockwise. 3. Problem 5.8. Hints: This is an asymmetric cross section and so you will need to calculate the centroid and three moments of inertia. To find the y position of the shear center you apply a V z alone, and to find the z position you apply a V y alone. Using point 2 as the origin: Centroid: (32cm, 16cm). Shear center wrt centroid: (-20.48cm, -27.52cm or shear center wrt point 2: ( 11.52cm, -11.52cm)...
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This note was uploaded on 06/06/2011 for the course EAS 4200C taught by Professor Kim during the Fall '09 term at University of Florida.
- Fall '09