Assignment 5 Solutions - CE93-Engineering Data Analysis...

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Unformatted text preview: CE93-Engineering Data Analysis Joan Walker, Spring 2011 Assignment 5 1. License plates a) 26 2 ( 10 4 ) 4! = 3407040 b) (26 2 25 2 ) 9 3 4 26 2 10 4 = 0.022 2. State name permutation Tennessee: ( 9 4 ) ( 5 2 ) ( 3 2 ) = 9! 4! 2! 2! 1! = 3780 Florida: 7! = 5040 Although Tennessee has more number of letters, Florida has more distinct letters. As a result of this, Florida generates more permutations. 3. Bus driver a) 0.9 12 =0.2824 b) 14 12 0.9 12 0.1 2 = 0.2570 c) 14 14 0.9 14 + 14 13 0.9 13 0.1 + 14 12 0.9 12 0.1 2 = 0.8416 4. Rainstorm a) ? = ? ???? = ? 8 2 ??? + 2 ? 2 ??? 8 2 ? = ? 3 24 2 + 2 ln ? 8 ? = 1 3 + 2 ln 8 2 ln 2 = 3.106 b) ? 3| ? 2 = ? 3 ? 2 = 2 ? 2 ??? 8 3 2 ? 2 ??? 8 2 = 2 ( 1 3 1 8 ) 2 ( 1 2 1 8 ) = 5 9 5. Storm runoff a) Find and draw PDF....
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This note was uploaded on 06/02/2011 for the course CIV ENG 93 taught by Professor Staff during the Spring '08 term at University of California, Berkeley.

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Assignment 5 Solutions - CE93-Engineering Data Analysis...

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