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Unformatted text preview: Q = 8.64 x 105 day m (1)(100 hectares)(10 4 hectare m 2 ) = 86.4 m 3 /day 1 What do you think of this? One might argue with the authors’ definition of l h ∆ ∆ ! I think, based on other solutions given by the authors, that the following is more correct: Q = 8.64 x 105 ( 10 1 10 + )(100)(10 4 ) = 95.0 m 3 /d (b) Travel time. Use the derivation below: Darcy velocity (cm/s) = v = K l h ∆ ∆ = K( t t h + ) h = head of leachate, t = soil thickness Seepage velocity (cm/s) = v ′ = porosity v Travel time = v t ′ If we substitute the above equations here, we get: Travel time = t) K(h (porosity) t 2 + = s/d) m)(86,400 10 cm/s(1 10 x 1 ) cm/m)(0.45 (100 m) (10 72 + (1 yr/365 d) = 128 yr 2...
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 Spring '11
 Parkin

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