105 - Surface Area and Volume Class Notes Lecture 10.5...

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Surface Area and Volume Class Notes Lecture 10.5
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Problem 1: Find the surface area and volume of the given cube.
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SA = 6s 2 5 in
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SA = 6(5 2 ) 5 in
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SA = 6(25) 5 in
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SA = 150 in 2 5 in
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V = S 3 5 in 150 in 2
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V = (5) 3 5 in 150 in 2
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V = 125 in 3 5 in 150 in 2
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The surface area is 150 square inches and the volume is 125 cubic inches. 125 in 3 5 in 150 in 2
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Problem 2: Find the surface area and volume for the square based pyramid.
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s = h 2 1 2 b 2 + 6 m 4 m 6 m
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s = 4 2 6 2 2 + 6 m 4 m 6 m
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s = 4 2 3 2 + 6 m 4 m 6 m
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s = 16 9 + 6 m 4 m 6 m
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s = 25 6 m 4 m 6 m
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s = 5 m 6 m 4 m 6 m
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rea of a triangle face = bh 1 2 s = 5 m 6 m 4 m 6 m
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A T = (6m)(5m) 1 2 s = 5 m 6 m 4 m 6 m
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A T = (30m 2 ) 1 2 s = 5 m 6 m 4 m 6 m
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A T = 15m 2 s = 5 m 6 m 4 m 6 m
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rea of a square base = b 2 A T = 15m 2 6 m 4 m 6 m
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A B = (6m) 2 A T = 15m 2 6 m 4 m 6 m
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A B = 36m 2 A T = 15m 2 6 m 4 m 6 m
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SA = 4(15m 2 ) + 36m 2 A B = 36m 2 A T = 15m 2 6 m 4 m 6 m
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SA = 60m 2 + 36m 2 A B = 36m 2 A T = 15m 2 6 m 4 m 6 m
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SA = 96m 2 A B = 36m 2 A T = 15m 2 6 m 4 m 6 m
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the pyramid is 96m 2 . A
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This note was uploaded on 06/04/2011 for the course MAT 115 68325 taught by Professor Elliot during the Spring '10 term at University of Phoenix.

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105 - Surface Area and Volume Class Notes Lecture 10.5...

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