# test - dm 'log;clear;output;clear;'; o options ps=50 ls=75...

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options ps=50 ls=75 pageno=1; o * Problem 1; data prostate1 ; infile 'K:\6360\Tests\Inclass\prostate1.txt' expandtabs firstobs=2; input lcavol lweight age svi \$ gleason psa ; run ; r PROC IMPORT OUT= prostate2 DATAFILE= "K:\6360\Tests\Inclass\prostate2.xls" DBMS=EXCEL2000 REPLACE; GETNAMES=YES; RUN; R data prostate; set prostate1 prostate2; lpsa = log(psa); drop psa; label lpsa = 'log of prostate specific antigen'; run; r * Problem 2; proc format; value \$svi 'N'='No' 'Y'='Yes'; run; r proc means data=prostate mean median var min max; class svi gleason; var lpsa; format svi \$svi.; run; r * Problem 3; proc univariate data=prostate cibasic alpha=0.1 mu0=2.28; var lpsa; run; r * Problem 4; proc freq data=prostate; tables svi*gleason / fisher; format svi \$svi.; run; r * Problem 5; goptions reset=all; title 'Histogram of lpsa'; proc univariate data=prostate; var lpsa; histogram / normal(fill mu=est sigma=est) cfill=red grid lgrid=35; run; r proc standard data=prostate out=out_set1 mean=0 std=1;

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## This note was uploaded on 06/06/2011 for the course STAT 4360 taught by Professor Park during the Spring '11 term at UGA.

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test - dm 'log;clear;output;clear;'; o options ps=50 ls=75...

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