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hw7sol

# hw7sol - STAT 4220 HW7 Solution 1 Problem 1(a Fitting the...

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STAT 4220 HW7 Solution 1 Problem 1 (a) Fitting the appropriate model yields the following: > summary(aov(g)) Df Sum Sq Mean Sq F value Pr(>F) factor(Day) 4 125.2 31.3 1.5343 0.2806 factor(Operator) 4 167.2 41.8 2.0490 0.1800 factor(Machine) 4 3424.8 856.2 41.9706 2.062e-05 *** factor(Method) 4 2857.6 714.4 35.0196 4.075e-05 *** Residuals 8 163.2 20.4 --- Signif. codes: 0 *** 0.001 ** 0.01 * 0.05 . 0.1 1 The Tukey multiple comparisons plot is given below. By inspection of the plot, we find that the pairs (B,A), (D,A), (E,A), (C,B), (D,B), (D,C) and (E,C) are all significantly different from one another. -20 -10 0 10 20 30 40 E-D E-C D-C E-B D-B C-B E-A D-A C-A B-A 95% family-wise confidence level Differences in mean levels of factor(Method) (b) From the ANOVA table above, we see that the factors Day and Operator are not significant sources of vari- ability. While we would definitely need to keep the Machine blocking factor in the model, we could simplify things by removing the other two blocking variables. At the cost of removing these two factors, we will not

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