**Unformatted text preview: **s s s K Q F = . 1 1 2 5 3 4 4 1 1 1 3 2 10 2000 2 4 2 2 2 u F u u u F- -- = --- - Delete the rows corresponding to u 1 and u 4 to obtain the global equations as [ ]{ } { } K Q F = 2 5 3 3 2 10 2 4 2000 u u- = -- Solving the above equation we obtain the displacements as: 3 3 2 3 5 10 m, 7.5 10 m u u--= - × = -× The cross section at 2.5 m from the left support is in Element 3. The force in an Element 3 is given by ( ) ( ) 3 (3) 4 3 AE P u u L =- Stress is given by P/A . Substituting the numbers we obtain ( ) ( ) ( ) 3 9 3 10 7.5 10 7.5MPa σ-=- -× = 1 m 1 m 1 m 1 m 1 1 m 1 m 2 3 1 2 3 4 1 2 3 0 u ( x ) mm x-5 -7.5 (m) 2000 N...

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