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# hw1a - Thomas Phillip Homework 1 Due 11:00 pm Inst Brodbelt...

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Thomas, Phillip – Homework 1 – Due: Sep 12 2007, 11:00 pm – Inst: Brodbelt 1 This print-out should have 22 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. Brodbelt CH301 Due Sept. 12, 2007, 11:00 pm 001 (part 1 of 1) 10 points What is the symbol for the element copper? 1. Cr 2. Cp 3. Cu correct 4. Co Explanation: The symbol for copper is Cu. 002 (part 1 of 1) 10 points A factor of 1 . 0 × 10 - 9 corresponds to the prefix 1. nano. correct 2. pico. 3. micro. 4. milli. Explanation: Nano refers to 1 . 0 × 10 - 9 . 003 (part 1 of 1) 10 points Express 0.0103240 in scientific notation. 1. 1 . 03240 × 10 - 3 2. 1 . 0324 × 10 - 3 3. 1 . 03240 × 10 - 2 correct 4. 1 . 0324 × 10 - 1 5. 1 . 0324 × 10 - 2 6. 1 . 03240 × 10 2 Explanation: The number is a fraction smaller than one, so the exponent is negative. The decimal must be moved 2 places, so the exponent on 10 must be - 2. 004 (part 1 of 1) 10 points What is the proper solution to the following equation? (150 + 2 . 5 + 36 . 75) ÷ (6 . 60 + 0 . 173) = 1. 28 correct 2. 27.9 3. 27.94183 4. 27.9418 5. 27.94 6. 27.942 7. 30 Explanation: The last position retained for the first addi- tion problem will be the tens position giving it 2 sigfigs. The last position retained for the second addition problem will be the hun- dredths position giving it 3 sigfigs. Therefore the final answer 27.94 needs to be rounded to 2 sigfigs: 28. 005 (part 1 of 1) 10 points How many kg are in 10.0 mg? 1. 1 . 00 × 10 - 5 kg correct 2. 1 . 00 × 10 - 7 kg 3. 1 . 00 × 10 - 3 kg 4. 1 . 00 × 10 - 4 kg 5. 1 . 00 × 10 - 6 kg Explanation:

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Thomas, Phillip – Homework 1 – Due: Sep 12 2007, 11:00 pm – Inst: Brodbelt 2 ? kg = 10 . 0 mg × 1 g 1000 mg × 1 kg 1000 g = 1 × 10 - 5 kg 006 (part 1 of 1) 10 points How many cubic inches (in 3 ) are in a 55.1 liter aquarium? 1. 3360 in 3 correct 2. 18,700 in 3 3. 129 in 3 4. 23.3 in 3 5. 162 in 3 Explanation: ? in 3 = 55 . 1 L × 1000 mL 1 L × 1 cm 3 1 mL × 1 in 2 . 54 cm 3 = 3360 in 3 007 (part 1 of 1) 10 points Calculate the density of methanol (CH 3 OH) if you know that there are 4.2 moles of methanol in 5.67 L. 1. 0.741 g/mL 2. 0.131 g/mL 3. 1334 g/mL 4. 11.34 g/mL 5. 0.0237 g/mL correct 6. 0.0431 g/mL Explanation: n = 4 . 2 mol V = 5 . 67 L d = 4 . 2 mol CH 3 OH 5 . 67 L × 32 g CH 3 OH 1 mol CH 3 OH × 1 L 1000 mL = 0 . 0237 g / mL 008 (part 1 of 1) 10 points How many electrons are present in a tin atom with a mass number of 119?
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hw1a - Thomas Phillip Homework 1 Due 11:00 pm Inst Brodbelt...

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