Thomas, Phillip – Homework 1 – Due: Sep 12 2007, 11:00 pm – Inst: Brodbelt
1
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printout
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have
22
questions.
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before answering.
The due time is Central
time.
Brodbelt CH301
Due Sept. 12, 2007, 11:00 pm
001
(part 1 of 1) 10 points
What is the symbol for the element copper?
1.
Cr
2.
Cp
3.
Cu
correct
4.
Co
Explanation:
The symbol for copper is Cu.
002
(part 1 of 1) 10 points
A factor of 1
.
0
×
10

9
corresponds to the prefix
1.
nano.
correct
2.
pico.
3.
micro.
4.
milli.
Explanation:
Nano refers to 1
.
0
×
10

9
.
003
(part 1 of 1) 10 points
Express 0.0103240 in scientific notation.
1.
1
.
03240
×
10

3
2.
1
.
0324
×
10

3
3.
1
.
03240
×
10

2
correct
4.
1
.
0324
×
10

1
5.
1
.
0324
×
10

2
6.
1
.
03240
×
10
2
Explanation:
The number is a fraction smaller than one,
so the exponent is negative.
The decimal
must be moved 2 places, so the exponent on
10 must be

2.
004
(part 1 of 1) 10 points
What is the proper solution to the following
equation?
(150 + 2
.
5 + 36
.
75)
÷
(6
.
60 + 0
.
173) =
1.
28
correct
2.
27.9
3.
27.94183
4.
27.9418
5.
27.94
6.
27.942
7.
30
Explanation:
The last position retained for the first addi
tion problem will be the tens position giving
it 2 sigfigs.
The last position retained for
the second addition problem will be the hun
dredths position giving it 3 sigfigs. Therefore
the final answer 27.94 needs to be rounded to
2 sigfigs: 28.
005
(part 1 of 1) 10 points
How many kg are in 10.0 mg?
1.
1
.
00
×
10

5
kg
correct
2.
1
.
00
×
10

7
kg
3.
1
.
00
×
10

3
kg
4.
1
.
00
×
10

4
kg
5.
1
.
00
×
10

6
kg
Explanation:
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Thomas, Phillip – Homework 1 – Due: Sep 12 2007, 11:00 pm – Inst: Brodbelt
2
? kg = 10
.
0 mg
×
1 g
1000 mg
×
1 kg
1000 g
= 1
×
10

5
kg
006
(part 1 of 1) 10 points
How many cubic inches (in
3
) are in a 55.1 liter
aquarium?
1.
3360 in
3
correct
2.
18,700 in
3
3.
129 in
3
4.
23.3 in
3
5.
162 in
3
Explanation:
? in
3
= 55
.
1 L
×
1000 mL
1 L
×
1 cm
3
1 mL
×
1 in
2
.
54 cm
¶
3
= 3360 in
3
007
(part 1 of 1) 10 points
Calculate the density of methanol (CH
3
OH) if
you know that there are 4.2 moles of methanol
in 5.67 L.
1.
0.741 g/mL
2.
0.131 g/mL
3.
1334 g/mL
4.
11.34 g/mL
5.
0.0237 g/mL
correct
6.
0.0431 g/mL
Explanation:
n
= 4
.
2 mol
V
= 5
.
67 L
d
=
4
.
2 mol CH
3
OH
5
.
67 L
×
32 g CH
3
OH
1 mol CH
3
OH
×
1 L
1000 mL
= 0
.
0237 g
/
mL
008
(part 1 of 1) 10 points
How many electrons are present in a tin atom
with a mass number of 119?
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 Fall '07
 Fakhreddine/Lyon
 Chemistry, Atom, Mole, pH, mol

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