{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Exam2Review - MAC 1105 Test 2 Review Sections R6(Complex...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
MAC 1105 Test 2 Review Sections R6 (Complex Fractions) - 1.8 (Absolute Value Equations) 1. Simplify each complex fraction: a. 7 x 2 5 x 25 49 x 2 b. 2 x 2 3 x 40 1 x 8 2 x + 5 + 4 8 x c. 3( x 2) 1 4( x + 2) 1 2( x 2 4) 1 2. Perform the operations in the complex number system. Write your answers in standard form. a) p 9( p 16 + p 36) b) (4 + i ) 2 (4 i ) 2 c) i 85 d) p (3 + 4 i )(4 i 3) e) 3 + 5 i 3 i 3. True or False: The equation 2 x 2 + 6 9 = 2 x 2 + 2 3 is an identity. 4. Find the solution set of each equation in the real number system: a) 3( x 4) 4( x 3) = x + 3 ( x 2) b) (3 x + 7) 2 = 2 c) 5 x x = 7 x 3 4 d) 10 x 1 = (2 x + 1) 2 e) x 4 x = 15 x + 4 5. What value(s) of x cannot be solutions to the following equation? Find the solution set of the equation: 3 x 2 3 x + 1 3 x = 4 x 6. Solve each inequality. Express your answer in interval notation and graph on a number line. a. 3 1 2( x + 5) 5 b. 1 3 4 3 + 2 5 x 3 5 x + 4 7. Solve each compound inequality. Write your solution in interval notation and graph on a number line. If there is no solution, say so.
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern