CBPTut2-solutions

CBPTut2-solutions - Chemical & Biochemical Processes...

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Tutorial 2 Reaction Engineering Question Solutions 1 – 3 1. ( 29 A batch X k t - - = 1 ln 1 = ( 29 min 9 . 160 8 . 0 1 ln 01 . 0 1 = - - t cycle = t batch + t fill + t empty + t clean = hr 3 . 4 min 4 . 258 60 10 250 20 250 9 . 160 = = + + + 2. Starting from the CSTR design equation: ( 29 ( 29 A A A A A A A A r X kC X kC X r X F V - = = - = 1 0 0 Here we make use of our old friend: C A = C A0 (1-X A ) Now we have to rearrange to make X A the subject of the equation: ( 29 A A A A r X X F kC V - = 1 0 0 0 0 0 0 1 A A r A A r A F kC V F kC V X + = Now we note that F A0 = v 0 C A0 , that is molar flow = volumetric flow x molar concentration and therefore 0 0 1 v k V v k V X r r A + = We substitute the known data in to the equation:
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473 . 0 04 . 0 ) 02 . 0 ( 8 . 1 1 04 . 0 ) 02 . 0 ( 8 . 1 = + = A X 47.3 % of the inlet reactant disappears to form product. The outlet concentration is calculated from C A = C A0 (1-X A ) = 15(1-0.473) = 7.905 Kmol m -3 . 3.
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CBPTut2-solutions - Chemical & Biochemical Processes...

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