tut 1- q 1 - 3

tut 1- q 1 - 3 - -3-6.215 318.15 3.0 × 10-2 3.14 ×...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Reaction Engineering Tutorial 1. 1. The Arrhenius equation is given by: , ( ) 1 3 2 298 1 343 1 314 . 8 55000 1 1 1 2 sec 092 . 0 40 . 18 10 5 40 . 18 1 2 - - - - - - = × = = = = k e e k k T T R E 2. This one is easy, huh! . 3. The same approach is used as for the example given in lecture 2. T (K) k (min -1 ) 1/ T (K -1 ) ln( k ) 273.15 4.7 × 10 -5 3.66 × 10 -3 -9.965 298.15 2.0 × 10 -3 3.35 × 10
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: -3-6.215 318.15 3.0 × 10-2 3.14 × 10-3-3.507 338.15 3.0 × 10-1 2.96 × 10-3-1.204 From slope of graph, -E/R = -12480 K, hence E = 103759 J mol-1 . Using one of the rate constants and temperatures from the table, substitute back in the Arrhenius equation to find that A ≈ 3 × 10 15 min-1 ....
View Full Document

{[ snackBarMessage ]}

Page1 / 2

tut 1- q 1 - 3 - -3-6.215 318.15 3.0 × 10-2 3.14 ×...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online