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Sp95Ex1Asol - t E r Sp 95 Exam 1:4 Name EGN 342i SHOW ALL...

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Unformatted text preview: t. E r Sp 95 Exam 1:4 Name EGN 342i] SHOW ALL WORK! Problem 1 (25 pin) Consider the function f(x) = 1‘“ - 1. A) Find an expression for the 2nd order truncated Taylor Series Expansion flea) evaluated at x=l.fllxa, where In is the point at which the series is expanded about. Leave your simplified answer in terms of IQ. Numeric constants should be rounded to 5 plaoes after the decimal point. B) If xo=1, find the true [clam error, as a per cent, in fzflfllxo). C) If Xg=1, find f3(l.fllx¢}. In Parts B) and C) express your answer rounded to 5 places after the decimal point. ....................................... WORK AREA ........................................... ANSWERS n) fzflfllw = , or = _ 9%. failmxu} = _ I 4‘ I I. 31395 Examl Name EGN3420 SHDWAILWDRK! ProblemZ (25pm) Uscflwsimpkmnpointimfim methodtofindfl'bemotof fix) =x-1n(x”+2) =u Startwithxa = Dandfillinthetablcheiflw. Roundallmtrieainflmmbleulalplam afiuthe decimal point. Do not Immd tl'beremlts of intermediate calculations. Sp 95 Exam 1 Name EGN 342B SHOW ALL WORK! Problemfi (25pm) Complete the first four iterations of the Biseetion Method to find the positive root of ftx) = If - 16. Complete the table below. Round all answers to 4 places after the decimal point. Sp 95 Exam 1 Name EGN 3420.011? AIL WORK! mm 4 (25 pts) A quadratic spline fit thru the data ptfints (1,1), (2,3), (3,6) and (4,12) is given below. 2x-1 15x52 f(x) = u1+bx+c 25x53 212-811-112 35x54 Finda,h,andc. 64' qS’. ’~ . EGH Mata EMm t 544%“; 63 find = [xi-nus“; PO $111K}: 901.91 + Q‘L‘Lg‘ji‘s-xfi a... 5;“ L33 {1+1‘3L 2-1 in __ a {1.9 Us + m1“ Err—1,5 * Hfiifltxv‘i EL [I ET :- [fi 'LK.D 1“] - £L[\.u\1$ fad 9L1. m‘j ’ G-tawun~n.wu$o -—-——.—-__ filflfl flaw-$1 : CD.H'-I1n 4):} C.) gr (- uw. I; '35 Let) ‘QILK.D‘\I + 4 in“: (0-011 3‘. '“ DAGW‘ID 1- .19 (fl.flOoool\] : 0.1;qu1 .. . . 1. S 15‘ - (:9 fi-UIL‘I: \L-‘mC fill-1'1) $.13 = InQFL+L\ iii-1:- :hrr‘i‘i‘ J :tfll‘i-LI‘ ;—__ . _ 1. ‘1“ ' fikfiu‘l ‘\n{1_ +L‘) LKACL‘; = D.hfi31'-1'1|E" 1L:%L$.3‘1mi‘ir+1‘j '- ‘iii ctkfizfil' u: 1n. {1_H3o‘15’3m"f ) =- 0,90%‘1‘i11-1 I- L 'm (1L1. +14 = ‘m {1.31‘SLEYH33311.0336151ng g 1. ‘F. ‘7. n “L a H: ‘3”:- 31 K {‘13 *1"! ~1AE3m-13Eq‘n-gm: l.|'z-1'S'G'$133 $513Ww}:\“(Mlvfllld(KUDHS’HHH)= LIEflHohES flu? {.113'101I‘L‘1 1t;- - 1.1a103319e *a‘ l.1?I%E?S’?—i'o *q" LzB‘S‘fii‘iLfiS 11:: LERSBSEH‘EG I $.- from c c: i¢.b‘151 ' 0-513" ~o.1.1§3 "L adv-0‘3": ”3.1301 5 L 12-5! —::).o\vtob ”3‘ 1.2.357 41m:- .23 (3) ‘55er = 1 1; D O I Z Z 3 3 “t 1):}: —'| ‘21 1 I. 1 13L: g.§ b1 : D filam= «4 ’1' 1L a: -_ 1,: _1 1.. Qfiflq = %‘-1 5m; ‘1 "‘5 ”FL—'5 LIE-IS z'fi 51H“: gaLuTmujfi 1211‘s): 15' 315 5-15 ...
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