Sp95Ex2Bsol - Sp 95 BEN 342D Exam 2 ’3) Name SHDW ALL...

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Unformatted text preview: Sp 95 BEN 342D Exam 2 ’3) Name SHDW ALL WDRK! Prublsm 1 (25 pts} Solve me. following system of equations using the Gauss Jordan Efiminsfinn Meflmd. s + h + c + d = 5 2s - b - c + 1! =25 s. + 31: + 2c - 441! = 11 2h - so + d = 111 Workman [1 1 1 1 s 2 —1—1 1 25 (Min— 1 3 2 —4 s ’5 11 2 —2 1 111 Ans a=_, h=___, cm#, d=_ '- Sp 95 HEN 3420 Exam 2 Name SHUW ALL WDRKI Pruitka (25 pts) Findtheequsfien uftheleastSqusresljnewhiehbestfitsfltehyperbelay = lfxflver the interval (1,5). De this. by generating 5 eqmlly spaced paints ever the interval (1,5) from the hyperbels. Find the sum ef the squares ef the residuals SSE. Round all calculsfienstedplaeessflerthedeeimslpeflu. gnu-nan... Work Area i i - i i I i i i - I - - r 1 - - - - - - - - - - - e - - - r e r e e r e e 1 e I e e 1 e I e e I I e I I e 1 e e 1 e e 1 e I 1 e I 1 I I I e I 1 I I 1 I I 1 I I 1 e e I 1 I e I 1 e e 1 + e 1 1 e I a e 1 o Ii Sp 95 HEN 342i} Exam 2 Name SHOW ALL WDRK! Problem 3 {25pm} E1 Consider the definite integral I =1; 3:; dx. Using Trapezoidai integration with a step size dx=l results in an approximate value IT = 2.443T5. A) Find the value of “a”. _ E) Using the correct value of “a”, apply,r Simpson’s 1f3 Formula with dx=5ifi and find Is, the approximation to the definite integral. C) Find the true relative error in Parts A) and El). Work Area B) Is = C} eT ['56) = Part A) Ans. A} a = nae) Part B} Sp 95 BEN 3420 Exam 2 Name SI-Iflw ALL WDRK! Problem 4 (251118} Using 'I‘rapemidal integration In appraximate the definite integral of fix} = sin from {J m m4, it is necessary tn keep the truncafinn are: below 2.35m: x m“. Find the number of requimd sub-intervals from I} to m4. u g q u y g I . g g . g g . . . a g I g g I a g p a I g q u g q g q y I q y I g . g g . g a 1 a a n a a I a n 1 I I 1 n I 1 n 1 1 n I I n I I I I 1 v n 1 v I I v v p o v - - - - - - - - r - - i I i i I i i It . g g q a g . . . . . . . . . . . . . . . a . a a o i a o 1 a a a o i a I a a I a I 1 a I a o I a n I a n 1 a I 1 o I a I I 1 n I a n I 1 n n 1 v n 1 v n o v v - - i i I i i i - i r I i i I u i i - i r a i -- ‘5 HS... E‘fikfl LB Saws- 9 Hh an... Jed "' ‘13 LE: -13; 4* <3 1 H3 (“133 '- 1 I 1' 'l " 5' 1 n 1 v. t ‘S 1 ‘1 -I: I 1 1-5" H D "‘3 -3 _‘ 1‘s I 5 Z “'1 a ‘3' '3 1 I ‘5” “5 I 0 2. ~z. n 1 1:: o I -‘1 ‘ to I. II i I. I t 1. 1. I- 15 1 I- I I M o n I I3. '5 D '* i'l3I'S ' ‘ .-- i“: Q I I D 2, .1.5' -5 oo—l'r’lg'u 5 r“) 7 .I 1‘ o G I {huh-S D 'L '1' ‘1“: 0*‘1 it 10 t D 37 a C! G 11'" D I “J II I l .l 1 5' i I 1 D I; a 1 } Illa I -S' D I I D *__S H I a a I III; " —E; a O 1 D I'S' I- D C: D I 1 {53‘ a D a I la a ‘5 :- :9 H I I D c: 1 1G 5 o D a 1 MD a I o I O a 1 H G I D C3 ‘l D D a I a Ifig C} C? I. :3 1"5' 0 D a '| {LG D D D I ‘D @ Y1}. “Us 51‘: :15 51":2—1835 2111:: 5: 2*:‘15‘3 mafia-awn; :1; (“math- 1 (15-39)”? ‘5 1".“1; Clo"- \‘E-ZE‘fiE an; 5' S5” \ a 581 = ‘3' S 11.01“. ‘3 15 so \1‘5 55' {111. S' 11%}?! v.5; Sr 1 -¢i.1‘1‘1‘5 1 -01%SD ‘57:: YD _ h... '1.- L I L ' 1Q; = (0.:13Le)+___fto.ua~1) -.-_ Q_01% Is. = ‘L = 1% 2.5 +~1 (03H 38+o. Lan + mam?) +1. (0» 515+ ‘3'- ‘33‘3 *O-W] 3 Edie} L {a {a .r ,_|' {a a") 118$L~na$hszfi13x - agik __ -1,5\ I 1 1L "'1 I. “f- ,l : HE'S, +2 g a 1 2.9335 Q-TLGLX t 1‘15 has '- 'I 2., 833- AH“: (_;,_1_:)w z -ma 1.10833 Mew Wynn! :5: a? -_ 2.5341135 11:73 In“ nfi-‘ic': ‘4; NI “(1.) q I | $ 1 fl —3 w; '1 a} ‘3 h “ Lgfifi'e’flw if» 1* L w l "’- ‘3 “a In : “ABS-s13??? “a 1 l 1 sh = 1_gg3qfitf¢3% 1km n. a”: H 1 7_asgqflihflfifiaa 1n \i n: 7’7 1w “I; (masmBm-EE‘J = 0.1% ND“ n 2 1mg ...
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Sp95Ex2Bsol - Sp 95 BEN 342D Exam 2 ’3) Name SHDW ALL...

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