Solución tarea 4

Solución tarea 4 - F isico 1 nero -...

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Fisico 1- £nero - Moyo 201 J Tarea 4 4:- La rQpidez. promcdio de uno molecula de n;trogeno en e\ oire es QP"'O J<.(- modctmen-tc b.'tO)(IOZrnls 'I su mos(/ e'5 4.€lBx )O-2b~ 0) Si uno molecola de n;troqeoo tardr' 3.QOX10- 15 S en qol peal" una pored y r-ebo- tar (on /9 tYlisma YQpiclc2 j pero movi cncJose en difeccion opUC'Sto 20001 es '0 QrclerQcioYl pton1~c1io dt" ia molecule, durante este inrt>rvolo de iiernrx/? Q b) Gut FlJerzo pfome'Cl;o e-jer('e fa m{)I~ClJla sobre leI ()(1r~ 0) 'Jf= Vi tot 0-= VI-Vi - -(O.iOXI0 2 m/s-<a.lOxn 2m b - -4.41 Xlo,sm/-s2. -t 3.(0)( 10-\3 S b) t~redrobret1\O\ecoa=rnxa =- (4."6~IO-2~K~ )(-4.4=1 rnl52.) = -2.0~X\Cf\ON - 10 " \ r rrolt'culo wbf{" p1,.~I::. --\- 2.0Cl 'x \0 ''I
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(O~ Uno mUJLr octo /20 Ib Dc-t~rmine oj So ~ en newtons y b) SJ Yl'Qn en Ki /ogrClmqs a) i Ib ~ 4.41BN 12.0 Ib z: 120 Ib (4.4"18 N ).::. 53~ N \ lib b) m= tl:) - 504 N 54.5 K<j q.BO mis' 9
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(<4.- 1 res ftJerz.Q~ que acit'nn sabre un objeto ~ prop:JrciaY1n por . -+ " A. --. ~ "") --+ '" F1 = L: 2.00 L + 2.00)) N) Fl = (5.00 l- 3.()()J N y F3 = (-45.o l) N EJ objeto expen mento una a(~Jeracion de 3.":l5mls 2 de- f1'Y:)gr'lltcxi. 0) ~GoOl e--s la dircccion de Ia a(~I~rnl'"lOn ~ b) CGuol e-~ 10 ma5Q de-! objcto? c) Si e) objcto '1I1icial menie eotfr en repo::n I 2Goa\ C5 so f"QpidC2 deoputS ~ 10 ~ 7 d)t Gobles son ICIS comp:mcnil""'S de vclocidad d~1 objcto dc~PJcs de 'OS? 0) iFx=. (-2.00{ t5.00t-45.0l) =(-420l)N t f4= (200]' -. "5.00]) = (-1.00J) N z F z: mo como 1o rnJSQ c s un esc-alar- 10 d;reccionde fa acel~rCtci6n t:"0 la mismo di~erl:lon de 10 Rrrzar<""Sul- rante 13 z: -ean- I 1- j .001 -= 1. 3b o 1-42.01 e= Ig(y~ + 1. 3fP = 181 0 b) F=mo.- rn= F = V[42.oyt ll.o(i 'N _ 42.01 _ a "3.15 m/s 2 3.15 c) ~ VI =- 0 +(3. .":J5 m/s a 'I ~Io ) ( IO~) ::: 3-=1-.5 m /5 a 18\0 vf= 31 .. 5rn/~ (rop",dez. d)
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LJf) soc-a de- cementa de 32.5 N de oeso cuclqa en equilibrio de ~ abmbr~0. Dos dr bs etlorr1:Jrt>s fOfrH.'1n onq u l 65 6, = ffi.cP Y 62= 25.0° con (0 hor'tzoniol. S i sE :supone qUi'."" el sls-lenYf e:>-t6 en et1 U ; Ii briO , ~n(oet1tre las 1.t>n.s'lcnes TI J Tz. . " T3 e-n lo s olomb tc: Nudo cemrntO - .-- odo +idle rom(lOnerne en 'Yl i f4=O ZR=O Z~=O' - 'I Go~bO.O + 12C~ 25.0=0 T, SenbC).(f . ... T2~t125. ..()-13-=:'O 15 - 325N==O "T3= 325}-J T 2 :::: 11 Go~b()·()() ------ T,~V\bb,o°-\ T \~(dtOO Set1~.(f=~ G~25-.()U Gos 25 00 ~.OCAT, -= 325 N 11 :::325N = 2.Cl6N T2 -= 2gb .- __ 1-.(1=\9 (OS25·0o T2=-\b3N =- , .... t
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This note was uploaded on 06/08/2011 for the course GA 5072L taught by Professor Comptonw during the Spring '11 term at ITESM.

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Soluci&amp;Atilde;&amp;sup3;n tarea 4 - F isico 1 nero -...

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