{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

quiz_07int_simpson(1)

# quiz_07int_simpson(1) - 702.039 The estimate of the same...

This preview shows pages 1–2. Sign up to view the full content.

07.03.1 Multiple-Choice Test Chapter 07.03 Simpson’s 1/3 Rule 1. The highest order of polynomial integrand for which Simpson’s 1/3 rule of integration is exact is (A) first (B) second (C) third (D) fourth 2. The value of 2 . 2 2 . 0 dx e x by using 2-segment Simpson’s 1/3 rule most nearly is 3. The value of 2 . 2 2 . 0 dx e x by using 4-segment Simpson’s 1/3 rule most nearly is 4. The velocity of a body is given by 5 1 , 2 ) ( = t t t v 14 5 , 3 5 2 < + = t t where t is given in seconds, and v is given in m/s. Using two-segment Simpson’s 1/3 rule, the distance in meters covered by the body from 2 = t to 9 = t seconds most nearly is

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
07.03.2 Chapter 07.03 07.03.2 5. The value of 19 3 ) ( dx x f by using 2-segment Simpson’s 1/3 rule is estimated as
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 702.039. The estimate of the same integral using 4-segment Simpson’s 1/3 rule most nearly is (A) ( ) ( ) ( ) [ ] 15 2 11 7 2 3 8 039 . 702 f f f + − + (B) ( ) ( ) ( ) [ ] 15 2 11 7 2 3 8 2 039 . 702 f f f + − + (C) ( ) ( ) [ ] 15 2 7 2 3 8 039 . 702 f f + + (D) ( ) ( ) [ ] 15 2 7 2 3 8 2 039 . 702 f f + + 6. The following data of the velocity of a body is given as a function of time. Time (s) 4 7 10 15 Velocity (m/s) 22 24 37 46 The best estimate of the distance in meters covered by the body from 4 = t to 15 = t using combined Simpson’s 1/3 rule and the trapezoidal rule would be (A) 354.70 (B) 362.50 (C) 368.00 (D) 378.80 For a complete solution, refer to the links at the end of the book....
View Full Document

{[ snackBarMessage ]}