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quiz_11fft_theoreticalfourier

# quiz_11fft_theoreticalfourier - Multiple Choice Test...

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11.06.1 Multiple Choice Test Chapter 11.06 Theoretical Development of Fast Fourier Transform 1. Based on 7 ,..... 2 , 1 , 0 = k 0 1 2 2 4 k k k + + = , for 5 = k , the corresponding values for 1 0 , k k and 2 k should be (A) { } { } 2 , 2 , 1 , , 2 1 0 = k k k (B) { } { } 1 , 1 , 3 , , 2 1 0 = k k k (C) { } { } 1 , 0 , 1 , , 2 1 0 = k k k (D) { } { } 0 , 1 , 1 , , 2 1 0 = k k k 2. Based on the following equations = = 1 0 4 0 1 2 0 1 0 1 2 2 0 ) , , ( ) , , ( k k n W k k k f k k n f 0 4 0 1 0 0 1 0 1 0 1 ) , , 1 ( ) , , 0 ( ) , , ( n W k k f W k k f k k n f + = 0 1 0 1 0 1 0 1 ) 1 , 1 , 1 ( ) 1 , 1 , 0 ( ) 1 , 1 , 0 ( ) 0 , 1 , 1 ( ) 0 , 1 , 0 ( ) 0 , 1 , 0 ( ) 1 , 0 , 1 ( ) 1 , 0 , 0 ( ) 1 , 0 , 0 ( ) 0 , 0 , 1 ( ) 0 , 0 , 0 ( ) 0 , 0 , 0 ( W f f f W f f f W f f f W f f f + = + = + = + = 0 4 1 0 4 1 0 4 1 0 4 1 ) 1 , 1 , 1 ( ) 1 , 1 , 0 ( ) 1 , 1 , 1 ( ) 1 , 1 , 0 ( ) 1 , 1 , 1 ( ) 0 , 1 , 1 ( ) 0 , 1 , 0 ( ) 0 , 1 , 1 ( ) 0 , 1 , 0 ( ) 0 , 1 , 1 ( ) 1 , 0 , 1 ( ) 1 , 0 , 0 ( ) 1 , 0 , 1 ( ) 1 , 0 , 0 ( ) 1 , 0 , 1 ( ) 0 , 0 , 1 ( ) 0 , 0 , 0 ( ) 0 , 0 , 1 ( ) 0 , 0 , 0 ( ) 0 , 0 , 1 ( W f f W f f f W f f W f f f W f f W f f f W f f

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quiz_11fft_theoreticalfourier - Multiple Choice Test...

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