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CHEM 112 Prac Exam 1 Workout

CHEM 112 Prac Exam 1 Workout - Uulll ill i The mass percent...

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Unformatted text preview: Uulll ill. i. The mass percent of acetone in a solution prepared by mixing 89.6 g acetone (C3H6O) and 72.1 g of H20 is: a} 44.6% 2} 80.6% @fig t 4] 13.9%“ 5] none ofthese .. . .. hits“ it s F is . ,WW%M« Wixm WMWXM«fi§% n W WWW” EMS g, WEEK he mass C f hfi it e? we {? RP I '3‘ first: ‘ I f» l semi? [gm J; 2. Which substance iisted below wouid be ost likely to dissolve in C6H6? 1] NH3 @ 3} no: 4] angel2 5] none would dissolve meshes. ate: 3. A gas dissolves in water, forming a saturated solution and giving off heat. When the solution is heated: i. the soiubiiity of the gas does not change. 2. the solubility of the gas increases. @he solubility of the gas decreases. 4. the dissolved gas causes the water to boil at a lower temperature. 5. no general prediction can be made about the solubility change. ‘ may. if i. an H’Jfibéflffi Aim! ‘4" is Qésgfjistx‘fi ffirlmér‘ffiie E 4. A solution of a nonelectrolyte dissolved in carbon. tetrachloride has a boiling point that is 430°C higher than the solvent. What is the mojaiity of the solute given kb is 5 .O3°C/m? E} 8'55 m (3] 08$" 3} 1 1'2 m 41,0395 m 5] none ofthese “strewn—um" f If I a [email protected] égefic I “ M M higher at”: a... E W, ..... i m m” m [a file} if???“ we .a‘”. 353% 5. Which aqueous solution has the lowest freezing point? til M7 «f'jiéi-‘f’h‘g‘zzffl‘ 99¢ t’ik (71 g M l] 0.20 M ethanol (a nonelectrolyte) @40 M NaNO3 3] 0.20 M CaBr2 0.47; “9" 4] 0.10 M KCl 5] all have the same freezing point . {H214 . . . . . is: n i 6. The Kc expressmn 4 1s for which reaction listed below? . - , r, s ‘ .1 ELK 1] 2 H2(g) + 02(g) Ft 2 H20(g) ' 136(8) + 4 H20(g) *3 1963543) t 4 H2(s) 3] 4 HgO(g) 1:2 4H2(g) + 2 02(g) 4] 2Na(s) +2H20(g) Ii 2Na01¥i(aq)+ H2(g) 5} none of these 7. For the reaction 2 H20 (g) 2:2 2 H20(g) + 02(g) the relation between Kl, and K0 is: “*9: 1. prKB 2 erKdRT) 3. Kp= ART? 4- Kp: c(RT)'3 :2” he. (KT Mi Ah?” We -- 8. The reaction 2N'O(g} + 2C0(g) 1d N2(g) + 2C02(g) was aliowed to reach equilibrium. Additional N0 gas was then injected. into the reaction chamber and equiiibrium was restored. Choose the correct statement below. 1. All concentrations remain the same. 2. A new equilibrium is obtained such that [N2] decreases. 3. The value ()ch increases. new equilibrium is obtained such that [CO] decreases. " ‘ {I’M _ 5. A new eQuilibrium is obtained such that both {C0} and {NZ} decrease. $.55 r 9. Calculate the moiarity of glucose (C614 1206) in a solution in which 10.0 g of glucose is dissolved in water and diluted to a float volume of 200 mL. ti: Wu rm {if .3 fllfigggw . .. , i. .- t. 07 9% it: if M i a rm... Manama o 4 in am} s 6 N; j gifigéffi M a $?gm WM? aft: new L 10. Water has a kf of l .86°C/m and a freezing point of 0°C. What is the freezing point of‘a solution made by dissolving 3.20 gram of CH3OH (a nonolectrolyte) in 100 grams of water? (:nirzwfli. igfi ;: Ji/fififlt‘fg 7 on time t “Early/WM o ream - Mme {WietZEi’Wfl i l. Calculate the osmotic pressure of an electrolyte solution that contains 0.0010 mole of K r and 0.00} 0 mole of BaC12 per liter of solution at 298 K. (R: 0.0821 L atm/mole K) g t: fitflggf im‘m m/ K game-g mrfl/égfifw #3 a“?! GWOMKW“ “3 firdd‘la M fiatfléékf fid’W i2. At high temperature, the following gas phase equilibrium is established: N205 :1 N20 + 202. Initially, 1.00 mole of N205 sealed into a 0.182 L flask. After equilibrium, the N20 concentration is 0.50 M. Calculate Kc . {W teem, l W . - {Wow a. s » m a,» W Nefia’ N a» 0 r 2 0‘2. at; W “W” t fists a (3 Li; #3 6, “6.9.5.5; M1595 + / at J ‘5? .. I 13. One (1.00) mole ofNO is placed in a 5.00 L container at 750°C. Ich m 2.06 x 10-2 at this temperature for 2 N0(g) zi N2(g) ~+~ 02(g) what is the equilibrium concentration ofNO(g)? a. (5 pts) Setup an iCe table. i '5; fig .2 fig 12,3051?! “fights h 1;”ng ’12; Nat?) My.» ) ’97 fiefi) .' ' 5:} eyes a a) i ii” i R see News wilt ti?” My {r a, z“); «i» 2‘ “t” a _ . . ,.. xg‘ J Eat”: @‘ngsg X {if {g‘z’gfi fig? E; 1’" b. (2 pts) Plug the e “values” from the iCe chart into the Kc expression, but do not solve. {my . "x . N e w . Mg (5‘4" (_ hi) i i ii 1 l to * ween w Mien as. taleleja... V. ‘ fit 24} fl *2; x MEWS—‘Wfig;4.—flr (E,— * i <9 1) {new «as l c. (2 pts) Solving the Kc expression using the quadratic formula yields two answers mathematically, 2.50 x lo—2 and M290 x 10—2, calculate the concentration ofNO(g). Tim? "we was) 6% M .w ~06) -. i ' " 7,1?! (new w Manges???) {wwwa .512 are) @E§Ejf .I’J'w' 14. The concentration of 02in blood is 3.0 x 10‘2 molal. At 370C (body temperature), Henry's law constant for oxygen is 1.8 x lO“3 molal/atm. What is the apparent pressure 01:02 (in atmospheres) in contact with the blood? L uuuuu (r up "#2,, M% t l” W 3“ LG 553%}: 3 a) a"? - a? . y m Wm %M i5. At a particular temperature, the solubility of lead bromide, PbBQ in pure water is 2.2 x 10'2 M The value owa is: We (to; [52:2 we” at W} a l l/ Tilt-=13?” Vlmi at age“ lotto tiefim 5t" ‘ lit? :1 @jfl‘fl . l f f ._ if N" a: 6:; fiagfige ' '- 16. Calculate the solubility ongI in a 0.100 M Nal solution at 25°C. The Ksp for Ag} is 850 x l047 at 250C. / £333” AN t if? "” keg @flfij I ; f; (L as e mail ZQX‘ltflJW) wt % Qw>¢€_ W‘X >55 affifi’ (film \ 1 La: as tofu! ...
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