HW4soln - PHYS3360/AEP3630 Electronic Circuits, Spring...

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PHYS3360/AEP3630 Electronic Circuits, Spring 2011, HW4 Solution 1 Negative Feedback Circuits Solutions 1. Save the plant. One possible solution is shown above. The other terminal of the lamp must to go 15 V and not ground because the light intensity is the same for either sign of the voltage on the lamp. The optional ° = 0.01 μF on ± ²³² is to get rid of AC noise. Of course, there should also be bypass caps on the ±15 V power supplies. In practice the op-amp would need to be a high power amplifier to drive a load requiring more than about 20 mA, but the circuit would identical. With negative feedback ± ²³² = ± ´²µ and ± ´²µ = ± ¶ℎ³·³ from the photocell. ± ²³² is held at a constant voltage selected by the user. Note: the negative feedback loop in this case is closed not with direct electrical connection, but via the light bulb – photocell path. The photocell in this circuit does not have to output voltage in exact proportionality
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This note was uploaded on 06/10/2011 for the course AEP 3630 taught by Professor Bozarov during the Spring '08 term at Cornell University (Engineering School).

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HW4soln - PHYS3360/AEP3630 Electronic Circuits, Spring...

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