HW04-solutions - Munoz (gm7794) HW04 TSOI (92515) 1 This...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Munoz (gm7794) HW04 TSOI (92515) 1 This print-out should have 18 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points Consider the circuit 100 V 2 F 4 F 3 F 5 F a b c What is the equivalent capacitance for this network? 1. C equivalent = 10 7 F 2. C equivalent = 7 3 F 3. C equivalent = 14 F 4. C equivalent = 7 F correct 5. C equivalent = 3 2 F Explanation: E B C 1 C 2 C 3 C 4 a b c Let : C 1 = 2 F , C 2 = 4 F , C 3 = 3 F , C 4 = 5 F , and E B = 100 V . The equivalent capacitance of capacitors C 1 and C 2 (parallel) is C 12 = C 1 + C 2 = 6 F . C 12 and C 3 are in series, so 1 C 123 = 1 C 12 + 1 C 3 = C 3 + C 12 C 12 C 3 C 123 = C 12 C 3 C 3 + C 12 = (6 F) (3 F) 6 F + 3 F = 2 F . C 123 and C 4 are parallel, so C = C 4 + C 123 = 7 F . 002 (part 2 of 2) 10.0 points What is the charge stored in the 5- F lower- right capacitor? 1. Q 1 = 1 , 100 C 2. Q 1 = 1 , 800 C 3. Q 1 = 500 C correct 4. Q 1 = 360 C 5. Q 1 = 710 C Explanation: Let : C 4 = 5 F and E B = 100 V . The charge stored in a capacitor is given by Q = C V , so, Q 4 = C 4 V = (5 F) (100 V) = 500 C . 003 10.0 points Consider the capacitor circuit Munoz (gm7794) HW04 TSOI (92515) 2 E B 6 F 2 F 8 F 3 F b a c Calculate the equivalent capacitance C ab between points a and b . Correct answer: 4 . 63158 F. Explanation: Let : C 1 = 6 F , C 2 = 8 F , C 3 = 2 F , and C 4 = 3 F . E B C 1 C 3 C 2 C 4 b a c For capacitors in series, 1 C series = 1 C i V series = V i , and the individual charges are the same. For parallel capacitors, C parallel = C i Q parallel = Q i , and the individual voltages are the same. Let c be the point between the two parallel sections. Let c be the point between the two parallel sections. The capacitance between a an c is C l = C 1 + C 3 = 6 F + 2 F = 8 F . The capacitance between b and c is C r = C 2 + C 4 = 8 F + 3 F = 11 F . Thus the capacitance between a and b is 1 C ab = 1 C l + 1 C r = C r + C l C l C r C ab = C l C r C l + C r = (8 F) (11 F) 8 F + 11 F = 4 . 63158 F . 004 (part 1 of 2) 10.0 points Consider two conductors 1 and 2 made of the same ohmic material; i.e. , 1 = 2 . Denote the length by , the cross sectional area by A ....
View Full Document

This note was uploaded on 06/10/2011 for the course PHY 302l taught by Professor Morrison during the Summer '08 term at University of Texas at Austin.

Page1 / 8

HW04-solutions - Munoz (gm7794) HW04 TSOI (92515) 1 This...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online