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Unformatted text preview: Munoz (gm7794) HW04 TSOI (92515) 1 This printout should have 18 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points Consider the circuit 100 V 2 F 4 F 3 F 5 F a b c What is the equivalent capacitance for this network? 1. C equivalent = 10 7 F 2. C equivalent = 7 3 F 3. C equivalent = 14 F 4. C equivalent = 7 F correct 5. C equivalent = 3 2 F Explanation: E B C 1 C 2 C 3 C 4 a b c Let : C 1 = 2 F , C 2 = 4 F , C 3 = 3 F , C 4 = 5 F , and E B = 100 V . The equivalent capacitance of capacitors C 1 and C 2 (parallel) is C 12 = C 1 + C 2 = 6 F . C 12 and C 3 are in series, so 1 C 123 = 1 C 12 + 1 C 3 = C 3 + C 12 C 12 C 3 C 123 = C 12 C 3 C 3 + C 12 = (6 F) (3 F) 6 F + 3 F = 2 F . C 123 and C 4 are parallel, so C = C 4 + C 123 = 7 F . 002 (part 2 of 2) 10.0 points What is the charge stored in the 5 F lower right capacitor? 1. Q 1 = 1 , 100 C 2. Q 1 = 1 , 800 C 3. Q 1 = 500 C correct 4. Q 1 = 360 C 5. Q 1 = 710 C Explanation: Let : C 4 = 5 F and E B = 100 V . The charge stored in a capacitor is given by Q = C V , so, Q 4 = C 4 V = (5 F) (100 V) = 500 C . 003 10.0 points Consider the capacitor circuit Munoz (gm7794) HW04 TSOI (92515) 2 E B 6 F 2 F 8 F 3 F b a c Calculate the equivalent capacitance C ab between points a and b . Correct answer: 4 . 63158 F. Explanation: Let : C 1 = 6 F , C 2 = 8 F , C 3 = 2 F , and C 4 = 3 F . E B C 1 C 3 C 2 C 4 b a c For capacitors in series, 1 C series = 1 C i V series = V i , and the individual charges are the same. For parallel capacitors, C parallel = C i Q parallel = Q i , and the individual voltages are the same. Let c be the point between the two parallel sections. Let c be the point between the two parallel sections. The capacitance between a an c is C l = C 1 + C 3 = 6 F + 2 F = 8 F . The capacitance between b and c is C r = C 2 + C 4 = 8 F + 3 F = 11 F . Thus the capacitance between a and b is 1 C ab = 1 C l + 1 C r = C r + C l C l C r C ab = C l C r C l + C r = (8 F) (11 F) 8 F + 11 F = 4 . 63158 F . 004 (part 1 of 2) 10.0 points Consider two conductors 1 and 2 made of the same ohmic material; i.e. , 1 = 2 . Denote the length by , the cross sectional area by A ....
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This note was uploaded on 06/10/2011 for the course PHY 302l taught by Professor Morrison during the Summer '08 term at University of Texas at Austin.
 Summer '08
 morrison
 Physics

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