HW10-solutions - Munoz (gm7794) HW10 TSOI (92515) This...

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Munoz (gm7794) – HW10 – TSOI – (92515) 1 This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 (part 1 oF 2) 10.0 points An object is 9 . 65 cm From the surFace oF a re±ective spherical Christmas-tree ornament 3 . 88 cm in radius. What is the apparent position oF the image? Correct answer: - 1 . 61527 cm. Explanation: 1 p + 1 q = 1 f = 2 R M = h ± h = - q p Convex Mirror 0 >f >p> 0 f<q< 00 <M< 1 Let : R =3 . 88 cm and p =9 . 65 cm . p is positive since it is in Front oF the mirror and R is negative since it is behind the mir- ror. A spherical Christmas-tree ornament is a convex mirror, so 1 p + 1 q = - 2 | R | . We are given the object distance, p and | R | . Inserting these values into the mirror equation and solving For q ,wefnd : q = - 1 2 R + 1 p = - 1 2 (3 . 88 cm) + 1 (9 . 65 cm) = - 1 . 61527 cm . 002 (part 2 oF 2) 10.0 points What is the magnifcation oF the image? Correct answer: 0 . 167386. Explanation: The magnifcation is given by: M = - q p = - - 1 . 61527 cm 9 . 65 cm = 0 . 167386 . 003 10.0 points Aconcavem irrorw itharad iuso Fcurvature oF 1 . 3misilluminatedbyacandlelocatedon the symmetry axis 3 . 3mFromthemirror. Where is the image oF the candle? Correct answer: 0 . 809434 m. Explanation: 1 p + 1 q = 1 f = 2 R m = h ± h = - q p Concave Mirror f> 0 >p>f f <q< 0 >m> -∞ f>p> 0 -∞ <q< 0 1 Let : f =0 . 65 m and p . 3m . ²rom the mirror equation 1 p + 1 q = 1 f = 2 R f = R 2 q = ± 1 f - 1 p ² - 1 = ± 1 (0 . 65 m) - 1 (3 . 3m) ² - 1 = 0 . 809434 m . 004 10.0 points AconcavemirrorhasaFocallengthoF36cm. What is the position oF the resulting image iF the image is inverted and 8 times smaller than the object? Correct answer: 40 . 5cm. Explanation:
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Munoz (gm7794) – HW10 – TSOI – (92515) 2 1 p + 1 q = 1 f = 2 R m = h ± h = - q p Concave Mirror f> 0 >p>f f <q< 0 >m> -∞ f>p> 0 -∞ <q< 0 1 Let : f =36cm and n =8 . Since the image is inverted, n = - 1 m .F r om the mirror equation 1 p + 1 q = 1 f and p q = n ,so 1 nq + 1 q = 1 f q = ( n +1) f n = (8 + 1) (36 cm) 8 = 40 . 5cm . 005 10.0 points Consider a concave mirror with radius R .An upright object is placed between the interval R 2 and R .
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HW10-solutions - Munoz (gm7794) HW10 TSOI (92515) This...

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