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TEST03-solutions

# TEST03-solutions - Version 028 TEST03 TSOI(92515 This...

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Version 028 – TEST03 – TSOI – (92515) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A real object is located 20 . 7 cm from a diverg- ing lens of focal length 39 . 3 cm. What is the magnification? 1. 0.575182 2. 0.588336 3. 0.540765 4. 0.627306 5. 0.55626 6. 0.608764 7. 0.5625 8. 0.655 9. 0.616482 10. 0.527597 Correct answer: 0 . 655. Explanation: Let : f = - 39 . 3 cm and p = 20 . 7 cm . 1 p + 1 q = 1 f M = h h = - q p Diverging Lens f < 0 > p > 0 f < q < 0 0 < M < 1 Using the lens equation, 1 q = 1 f - 1 p = p - f f p q = f p p - f = ( - 39 . 3 cm) (20 . 7 cm) 20 . 7 cm - ( - 39 . 3 cm) = - 13 . 5585 cm , so M = - q p = - - 13 . 5585 cm 20 . 7 cm = 0 . 655 . 002 10.0 points The smallness of the critical angle θ c for di- amond means that light is easily “trapped” within a diamond and eventually emerges from the many cut faces. This makes a dia- mond more brilliant than stones with smaller n and larger θ c . Traveling inside a diamond, a light ray is incident on the interface between diamond and air. What is the critical angle for total internal reflection? The refraction index for diamond is 2 . 3 . 1. 25.1843 2. 24.0895 3. 21.8234 4. 25.7715 5. 28.4369 6. 22.1702 7. 23.3799 8. 27.4406 9. 23.9854 10. 26.9035 Your answer must be within ± 0.1% Correct answer: 25 . 7715 . Explanation: For diamond, the critical angle is sin θ c = 1 n = 1 2 . 3 θ c = 25 . 7715 . 003 10.0 points Consider a double slit experiment as shown in the sketch. y L d S 1 S 2 θ viewing screen θ δ What is the phase angle di ff erence φ and corresponding path di ff erence δ of the 2nd minimum on the screen? 1. φ = 2 π , δ = λ

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Version 028 – TEST03 – TSOI – (92515) 2 2. φ = π , δ = λ 2 3. φ = 4 π , δ = 2 λ 4. φ = 7 π , δ = 2 λ 5. φ = 6 π , δ = λ 6. φ = 8 π , δ = 3 λ 2 7. φ = 10 π , δ = 3 λ 2 8. φ = 9 π , δ = 2 λ 9. φ = 3 π , δ = 3 λ 2 correct 10. φ = 5 π , δ = λ 2 Explanation: r 2 r 1 y L d S 1 S 2 θ = tan - 1 y L viewing screen δ d sin θ r 2 - r 1 P O S 2 Q S 1 90 Q 2 π or 360 φ δ λ = 500 nm 0 1 - 1 0 90 180 270 360 0 π / 2 π 3 π / 2 2 π φ 2 π = δ λ = d sin θ λ = d λ y L 2 + y 2 d λ y L Basic concept: Double slits interference: the phase angle di
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TEST03-solutions - Version 028 TEST03 TSOI(92515 This...

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