{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

SolutionPracticeFinal

# SolutionPracticeFinal - Math242 — Practice Final Film...

This preview shows pages 1–10. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Math242 — Practice Final April 22, 2010 Film] Exam: One piece of paper (1}. X 8.5) with handwriting (not photocopy) is allowed; Two more challenging 13111131631113 for 13011118 points. 1. Find the general solution of 11 ‘ ‘ ‘ :31 = 1 -+~ (1:2 + (0'2 + x2312, (1:1: ﬁiiEkEGﬁ 5% ”fo;)% fUJi’E) ﬁka—XHiﬂ M. mfg/magi 2. Find the particulaz Solution of 3. Find the general sohﬁnion 0f :r'jy’ : may — y‘B. \ , X} 3 \$3th W” m ‘ «:2; ck? 4. Find the pmtimlar salution of (ET + yew + (By +s17€3my)y’ : 0., 391(0) = 2 3.3.! «39% 2': QTMWW Hack Q KW )5 ﬁi‘ﬁ Mi ﬂ X _ 3533 Mé‘g 53> WW 1? 5i 3 W <~3§¥am W‘ﬁ-Hm 2% (WW Mm; (\$39ng g C; 5. Find the critical points of the given differential equation, determine Whether criticai point is stabie 01' unstaiﬁe, and soive the differential ecgiation explicitly. (1:17 . Ezrr w5zrw+4u im im" ﬁM W1: xiv-MM; jiK'ﬁﬂiﬂk)‘ D ‘ Kg’ﬁ' Xi“:- ﬁmmmgkﬁimm .25: OT kt; ﬁmmm k2: §K2§ﬁﬁt \fsﬁihim ) Fab W Wm M \$0M % W) _... gw‘mm 2km) . 6. Use the RungowKutta method with step size h = 0.5 to approxhnate the solution on the ﬁlterval [(3, 1]. 59% k W? m i {a 3; 35) JYUJV k . 5W)“; H 9:73th : 3:2 +112? 5W Li . gr 5:“25 6 7. Find the general solution of 612;“) + 113;” + 4y m 0. 3% MW 2 ©ka Eta \$me (4%" J: H ﬂ Ar: 0» (2m 1} WW :0 ”333g 1 i: é§£ ,, Effliéﬁ 9i? 8. Find a. particular solution of 1 ML 33> Br;- 3%“) A: v” fawn ? gm? ﬁwwm 5K 0LT WT 5+5 9‘ (a): Find the Lawlace trausfm-m of ﬁt) 2 (3‘2" sin 37rt; (13):?in the inversse Laplam transform of F(s )— — JUTANTW 5 5k IL U OLWWT £5,555 55555 ”3T "-55% «:2:- aim: T“ 5 CH Q m T (Sui-TATE? 55.4%,” r 5 5 ((5,339 U 5* 5T " 55555555525) 552 5‘5 (55556555) T BTSMTWVH (CSTTTSTJT 5:»: 2 :95 T36"; '57; 'l 10. U 86 the: Laplace tral'lsfoml to solve initial value problem x”+42:’+13x=te”‘; :r(())=0, g;’(0)\$2. lMW*cUﬂm:SMWﬁﬁwzw%> glam} m S‘MW msmwx’w) . :2 3"” X52) «:2; ,. . "l §m\$a+%Mbw €&@W \$7 W . l __ 915% — Wislwié‘g)’ 10 l 3; null, mm 506 albamwje'l/W w; ‘ ...
View Full Document

{[ snackBarMessage ]}