# ch11 - Chapter 11 Problem 2 With z = 2.58 and e = 0.05 the...

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Chapter 11 Problem 2: With z = 2.58 and e = 0.05, the number of observations needed for each work element is: Work Element 1: n = 2 10 . 1 20 . 0 05 . 0 58 . 2 × = 89 Work Element 2: n = 2 80 . 0 10 . 0 05 . 0 58 . 2 × = 42 Work Element 3: n = 2 90 . 0 15 . 0 05 . 0 58 . 2 × = 74 Work Element 4: n = 2 00 . 1 10 . 0 05 . 0 58 . 2 × = 27 Sample size needed is 89. Problem 4: Work Element 1: n = 2 40 . 2 60 . 0 05 . 0 58 . 2 × = 167 Work Element 2: n = 2 50 . 1 20 . 0 05 . 0 58 . 2 × = 48 Work Element 3: n = 2 85 . 3 10 . 1 05 . 0 58 . 2 × = 218 Work Element 4: n = 2 55 . 2 85 . 0 05 . 0 58 . 2 × = 296 Work Element 5: n = 2 60 . 1 40 . 0 05 . 0 58 . 2 × = 167 Work Element 6: n = 2 50 . 2 50 . 0 05 . 0 58 . 2 × = 107 Sample size needed is 296 Percentage increase in sample size due to the higher confidence is 73.1%.

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Problem 6: ST = (NT)(AF), where AF = 1 + PFD = 1 + 0.15 = 1.15 ST element 1 = (1.14)(1.15) = 1.311 ST element 2 = (0.85)(1.15) = 0.978 ST element 3 = (1.14)(1.15) = 1.012 ST element 4 = (0.99)(1.15) = 1.139 ST job = (1.311 + 0.978 + 1.012 + 1.139) = 4.440
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ch11 - Chapter 11 Problem 2 With z = 2.58 and e = 0.05 the...

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