hw10sols

# hw10sols - C O250/CM340 I NTRODUCTION TO O PTIMIZATION HW...

This preview shows pages 1–2. Sign up to view the full content.

CO250/CM340 INTRODUCTION TO OPTIMIZATION - HW 10 SOLUTIONS Exercise 1 (20 marks) . (a) The cone generated by { (1 , 0 , 0) , (0 , 1 , 0) , (0 , 0 , 1) } is C = { x : x = λ 1 (1 , 0 , 0) + λ 2 (0 , 1 , 0) + λ 3 (0 , 0 , 1) , λ i 0 i } = { ( λ 1 2 3 ) : λ i 0 i } . Le x 1 and x 2 denote two points in C , where x i = ( λ i 1 i 2 i 3 ) for i = 1 and 2 . Then for any 0 λ 1 , λx 1 + (1 - λ ) x 2 = λ ( λ 1 1 1 2 1 3 ) + (1 - λ )( λ 2 1 2 2 2 3 ) = ( λλ 1 1 + (1 - λ ) λ 2 1 ,λλ 1 2 + (1 - λ ) λ 2 2 ) ,λλ 1 3 + (1 - λ ) λ 2 3 ) = ( μ 1 2 3 ) where each μ i 0 because of the conditions on λ and the λ i j . Hence ( μ 1 2 3 ) C . Since this was true for any two points x 1 and x 2 C , it follows that C is convex. To ﬁnd extreme points, consider x C . Then clearly x 1 := 1 2 x and x 2 := 3 2 x are both in C . Moreover, x = 1 2 x 1 + 1 2 x 2 . Hence, x 1 cannot be extreme if x 1 6 = x 2 . This occurs whenever x 6 = 0 . So the only possible extreme point of C is 0 . To show that x = 0 is an extreme point, we assume that it is properly contained in the interval joining distinct points x 1 , x 2 C , and reach a contradiction. Proper containment implies that x = λx 1 + (1 - λ ) x 2 for some 0 < λ < 1 , and also x 1 6 = x = 0 , so one of the coordinates of x 1 is nonzero. Without loss of generality, let it be the ﬁrst coordinate, x 1 1 . Since 0 = x 1 = λx 1 1 + (1 - λ ) x 2 1 , it follows that x 2 1 < 0 , which contradicts x 2 C . (b) Yes it is convex, and the only extreme point is 0 . (The proof, not required here, is similar to (a)’s proof.) (c) S is the intersection of the sets of feasible solutions of the two LP’s. We know that the set of feasible solutions of an LP is convex, and that the intersection of two convex sets is convex. Thus S is convex. (d) We know that the set of feasible solutions of an LP is convex. Also c T x = 1 is a hyperplane, which is the intersection of two halfspaces, c T x = 1 and c T x 1 , and we know that all halfspaces are convex. Note that

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 5

hw10sols - C O250/CM340 I NTRODUCTION TO O PTIMIZATION HW...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online