Week 6 Individual Assignment

# Week 6 Individual Assignment - Charles Blackstone...

This preview shows pages 1–3. Sign up to view the full content.

Charles Blackstone Individual Week 6 Assignment 5/2/2011 Chapter 3 Exercise 88 Solution: Team Salaries: Mean= 73.06 Median= 66.20 Standard Deviation= 34.23 For the Stadium Age: Mean= 28.20 Median= 17.50 Standard Deviation= 25.94 For the Seating Capacity: Mean= 45912.6 Median= 44174 Standard Deviation= 5894.2 Chapter Exercise 56 Assume the likelihood that any flight on Northwest Airlines arrives within 15 minutes of the scheduled time is .90. We select four flights from yesterday for study. a. What is the likelihood all four of the selected flights arrived within 15 minutes of the scheduled time? P(x=4) = 0.65610 b. What is the likelihood that none of the selected flights arrived within 15 minutes of the scheduled time? P(x=0) = 0.00010 c. What is the likelihood at least one of the selected flights did not arrive within 15 minutes of the scheduled time? P (x≥1) = 0.99990 n = 4, p = 0.9, q = 0.1 Binomial Distribution X p(x)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
0 0.00010 1 0.00360 2 0.04860 3 0.29160 4 0.65610 Exercise 64 An internal study by the Technology Services department at Lahey Electronics revealed company employees receive an average of two emails per hour. Assume the arrival of these emails are approximated by the Poisson distribution. a. What is the probability Linda Lahey, company president, received exactly 1 email between 4 P.M. and 5 P.M. yesterday? P(x=1) = 0.270670566 b. What is the probability she received 5 or more email during the same period? P (x≥5) = 0.016563608 c. What is the probability she did not receive any email during the period? P(x=0) = 0.135335283 Exercise 50 Fast Service Truck Lines uses the Ford Super Duty F-750 exclusively. Management made a study of the maintenance costs and determined the number of miles traveled during the year followed the normal distribution. The mean of the distribution was 60,000 miles and the standard deviation 2,000 miles. Mean = 60,000, St dev = 2000, Normal Distribution a. What percent of the Ford Super Duty F-750s logged 65,200 miles or more?
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 7

Week 6 Individual Assignment - Charles Blackstone...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online